Leetcode
104. Maximum Depth of Binary Tree
Leeter
2021. 11. 12. 16:21
Description:
Given the root of a binary tree, return its maximum depth.
A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
'''
[1] bottom-up)
code::
def maxDepth(self, root: Optional[TreeNode]) -> int:
if not root:
return 0
if not root.left and not root.right:
return 1
left_depth=self.maxDepth(root.left)
right_depth=self.maxDepth(root.right)
return max(left_depth,right_depth)+1
-T/C: O(n)
-S/C: O(h)
'''
'''
[2] top-down)
idea::
update depth
code::
def maxDepth(self, root: Optional[TreeNode]) -> int:
return self.getDepth(root,0)
def getDepth(self,root,depth):
if not root:
return depth
return max(self.getDepth(root.left,depth+1),self.getDepth(root.right,depth+1))
-T/C: O(n)
-S/C: O(h)
'''
class Solution:
def maxDepth(self, root: Optional[TreeNode]) -> int:
return self.getDepth(root,0)
def getDepth(self,root,depth):
if not root:
return depth
return max(self.getDepth(root.left,depth+1),self.getDepth(root.right,depth+1))